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Presentation On Single Phase Half Bridge Invertor

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Published in: Physics
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The presentation will describe you about the Single Phase Half Bridge Invertor.

Sarath M / Abu Dhabi

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Qualification: B.Sc Physics , BTech in Electrical & Electronics Engineerin, PMP Aspirant with 150 PDU

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  1. Single-phase half-bridge inverter
  2. Operational Details 2 3-wire DC source 2 R 1 DI a Consists of 2 choppers, 3-wire DC source Transistors switched on and off alternately Need to isolate the gate signal for QI (upper device) Each provides opposite polarity of Vs/2 across the load
  3. QI on, Q2 off, vo - V /2 Peak Reverse Voltage of Q2
  4. QI off, Q2 on v , -vs/2
  5. Waveforms with resistive load Fundamental current,
  6. Look at the output voltage Fundamental current, iol rms value of the utput voltage, Vo 2 O O
  7. Fourier Series of the instantaneous output voltage a — + E (an COS(not) + bn sin(not)) 2 ao,an = 0 1 — (ot) 2 2 — sin(not)
  8. rms value of the fundamental component sin not 01 1 2vs = 0.45vs
  9. When the load is highly inductive 02 02
  10. Turn off QI at t = T /2 Current falls to 0 via D2, L, Vs/2 lower vs/2 vs/2 L 02
  11. Turn off Q2 at t = To Current falls to 0 via DI, L, Vs/2 upper vs/2 vs/2 LC2 02
  12. Load Current for a highly inductive load Transistors are only switched on for a quarter-cycle, or 900
  13. Fourier Series of the output current for an i R -k jnct)l-u RL load sin(not — On) R2 -k (noL) = tan
  14. Fundamental Output Power In most cases, the useful power POI = V I cosq 01 01 01 = 1021R 2
  15. DC Supply Current If the inverter is lossless, average power absorbed by the load equals the average power supplied by the dc source. vs (t)is (t)dt vo (t)io (t)dt For an inductive load, the current is approximately sinusoidal and the fundamental component of the output voltage supplies the power to the load. Also, the dc supply voltage remains essentially at Vs.
  16. DC Supply Current (continued) — 10 cos(01)
  17. Performance Parameters Harmonic factor of the nth harmonic (HFn) on 01 for n>l = rms value of the nth harmonic component VOI = rms value of the fundamental component
  18. Performance Parameters (continued) Total Harmonic Distortion (THD) Measures the "closeness" in shape between a waveform and its fundamental component THD = 01 1 v 02n)2
  19. Performance Parameters (continued) Distortion Factor (DF) Indicates the amount of HD that remains in a particular waveform after the harmonics have been subjected to second-order attenuation. 1 01 n=2,3,... on 2 voln 1 on 2 n for n>l
  20. Performance Parameters (continued) Lowest order harmonic (LOH) The harmonic component whose frequency is closest to the fundamental, and its amplitude is greater than or equal to 3% of the amplitude of the fundamental component.
  21. Single-phase full-bridge inverter Load
  22. Operational Details Load t Consists of 4 choppers and a 3-wire DC source QI-Q2 and Q3-Q4 switched on and off alternately Need to isolate the gate signal for QI and Q3 (upper) Each pair provide opposite polarity of Vsacross the load
  23. QI-Q2 on, Q3-Q4 off, vo - V
  24. Q3-Q4 on, QÅ‚-Q2 off, vo - V Loa d
  25. When the load is highly inductive Turn QI-Q2 off — Q3-Q4 off Load
  26. Turn Q3-Q4 off - QI-Q2 off Load
  27. Load current for a highly inductive load
  28. Example 6.3 - MultiSim7 Cl IOOOuF XFGI IOOOuF QI 1 vov 1 vov o Dl DIODE_VIRTUAL 10 Ohm 31.5mH DIODE_VIRTUAL c 112uF DIODE_VIRTUAL o J 1 vov 02 IVO v DIODE_VIRTUAL
  29. Example 1 v ov 6.3 using the scope xscl DI DIODE VIRTUAL o —L Vs -=-220 v IOOOuF XFGI IOOOuF L C 31.5mH 112uF 1 v ov 1 Ohm 9 Ohm DIODE VIRTUAL DIODE VIRTUAL DIODE VIRTUAL O 1 v ov 1 v ov

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